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| You need just one-line function to evaluate the number of days in a month (while taking leap years into account, of course). The trick is to use the DateDiff and DateSerial functions to calculate the difference between the first day of the current month and the first day of the subsequent month : |
 Click here to copy the following block | Function DaysInMonth(ByVal Month As Integer, ByVal Year As Integer) As Integer
DaysInMonth = DateDiff("d", DateSerial(Year, Month, 1), DateSerial(Year, _
Month + 1, 1))
End Function |
At first it seems that you need an If statement to deal with December in a separate block of code, but the DateSerial function returns a consistent value even when Month > 12.
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Submitted By :
Nayan Patel
(Member Since : 5/26/2004 12:23:06 PM)
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Job Description :
He is the moderator of this site and currently working as an independent consultant. He works with VB.net/ASP.net, SQL Server and other MS technologies. He is MCSD.net, MCDBA and MCSE. In his free time he likes to watch funny movies and doing oil painting. |
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View all (893) submissions by this author
(Birth Date : 7/14/1981 ) |
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