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Get the full directory path of a file passed in

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Click here to copy the following block
Public Function GetTheFilePath(ByVal strFile) As String
  Files = Split(strFile, "\")
  For I = 0 to (UBound(Files) - 1)
    FilePath = FilePath & Files(I) & "\"
  Next
  GetTheFilePath = FilePath
End Function

'///////////////////////////////////////////////////////////////////
'//Usage
'///////////////////////////////////////////////////////////////////
'This is a very simple way to get just the full directory path of
'a file passed in.
'example:
'MyFilePath = GetTheFilePath("C:\testing\jim\file.txt")
'will return "C:\testing\jim\"


Submitted By : Nayan Patel  (Member Since : 5/26/2004 12:23:06 PM)

Job Description : He is the moderator of this site and currently working as an independent consultant. He works with VB.net/ASP.net, SQL Server and other MS technologies. He is MCSD.net, MCDBA and MCSE. In his free time he likes to watch funny movies and doing oil painting.
View all (893) submissions by this author  (Birth Date : 7/14/1981 )


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